Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems - Page 224: 5.154


Please see the work below.

Work Step by Step

As we know that $PV=nRT$ This can be rearranged as: $n=\frac{PV}{RT}$ We plug in the known values to obtain: $n=\frac{96747\times 0.00126}{8.31\times 295}=0.0498moles$ The chemical reaction is : $Zn+2HCl\rightarrow ZnCl_2+H_2$ Moles ratio of $Zn:H_2=1:1$ so moles of Zn=0.049 $Mass \space of \space Zn=moles\times molar\space mass=0.0498\times 65.39=3.26g$ $percentage \space mass \space of Zn=\frac{3.26}{6.11}\times 100\%=53.4\%zinc$
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