Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 5 - Gases - Questions & Problems: 5.117

Answer

Please see the work below.

Work Step by Step

We know that $number \space of \space moles \space of water\space evaporated=\frac{PV}{RT}$ We plug in the known values to obtain: $number \space of \space moles \space of water\space evaporated=\frac{0.2467\times 2.5}{0.0821\times 338}=0.0222moles$ $Mass\space of\space water \space evaporated=0.0222\times 18=0.40g$
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