Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 4 - Reactions in Aqueous Solutions - Questions & Problems: 4.63

Answer

Please see the work below.

Work Step by Step

We know that $60.0mL=0.0600L$ $mol=M\times L$ $mol\space MgCl_2=\frac{0.100mol\space MgCl_2}{1 L\space soln}\times 0.0600\space L\space soln=6.00\times 10^{-3}mol\space MgCl_2$
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