## Chemistry 12th Edition

We know that $60.0mL=0.0600L$ $mol=M\times L$ $mol\space MgCl_2=\frac{0.100mol\space MgCl_2}{1 L\space soln}\times 0.0600\space L\space soln=6.00\times 10^{-3}mol\space MgCl_2$