Answer
Sample 1 : Empirical formula = $PtCl_{2}$
Sample 2 : Empirical formula = $PtCl_{4}$
Work Step by Step
Sample 1
Percentage of Chlorine = 26.7
Hence percentage of Platinum = 100 –(26.7) = 73.3
Relative no.of atoms =Pecentage/Atomic mass
Pt $73.3\div195.1$ = 0.376
Cl $26.7\div35.5$ = 0.752
Divide by smallest relative no.of atoms (here 0.376)
$0.376\div0.376$ = 1
$0.752\div0.376$ = 2
Convert to the whole number
1
2
Empirical formula = $PtCl_{2}$
Sample 2
Percentage of Chlorine = 42.1
Hence percentage of Platinum = 100 –(42.1) = 57.9
Relative no.of atoms =Pecentage/Atomic mass
Pt $57.9\div195.1$ = 0.297
Cl $42.1\div35.5$ = 1.186
Divide by smallest relative no.of atoms (here 0.297)
$0.297\div0.297$ = 1
$1.186\div0.297$ =3.99
Convert to the whole number
1
4
Empirical formula = $PtCl_{4}$
