Answer
The green precipitate is $CuF_{2}$
When $KCl$ is added, the bright green solution is due to formation of $CuCl_{4}^{2-}:$
$Cu^{2+}(aq) + 4Cl^{-}(aq) -> CuCl_{4}^{2-}(aq)$
Work Step by Step
The green precipitate is $CuF_{2}$
When $KCl$ is added, the bright green solution is due to formation of $CuCl_{4}^{2-}:$
$Cu^{2+}(aq) + 4Cl^{-}(aq) -> CuCl_{4}^{2-}(aq)$