Answer
When an isotope is above the belt of stability, the n/p ratio is too high. The only way to reduce this is by $\beta$-emission; the process turns a neutron into a proton. Direct neutron emission does not occur.
$N_{7}^{18} -> O_{8}^{18} + \beta_{-1}^{0}$
Work Step by Step
When an isotope is above the belt of stability, the n/p ratio is too high. The only way to reduce this is by $\beta$-emission; the process turns a neutron into a proton. Direct neutron emission does not occur.
$N_{7}^{18} -> O_{8}^{18} + \beta_{-1}^{0}$
