Answer
0.010 V
Work Step by Step
$E=E^{\circ}-\frac{0.0257}{n}\ln Q$
$E^{\circ}=0$ as the electrodes are identical.
Number of electrons transferred $n=2$
Then, we get
$E=0-\frac{0.0257}{2}\ln\frac{0.24\,M}{0.53\,M}=0.010\,V$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 18 - Electrochemistry - Questions & Problems - Page 851: 18.36
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