Answer
Please see the work below.
Work Step by Step
As we know, $H_2CO_3$ neutralizes $NaOH$, and the reaction is given as
$CO_2+H_2O\rightarrow H_2CO_3$
Chemistry 12th Edition
by Chang, Raymond; Goldsby, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0078021510
ISBN 13:
978-0-07802-151-0
Chapter 16 - Acid-Base Equilibria and Solubility Equilibria - Questions & Problems - Page 766: 16.44
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