Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 16 - Acid-Base Equilibria and Solubility Equilibria - Questions & Problems: 16.44

Answer

Please see the work below.

Work Step by Step

As we know, $H_2CO_3$ neutralizes $NaOH$, and the reaction is given as $CO_2+H_2O\rightarrow H_2CO_3$
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