Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 16 - Acid-Base Equilibria and Solubility Equilibria - Questions & Problems - Page 765: 16.27

Answer

Please see the work below.

Work Step by Step

We know that $molar\space mass=\frac{weight}{number\space of \space moles}=\frac{0.2688}{0.0013}=202\frac{g}{mol}$
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