Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 15 - Acids and Bases - Questions & Problems - Page 712: 15.60


We can deduce that, the stronger the acid, the weaker the conjugate base will be.

Work Step by Step

If we have 2 values multiplying to form a constant, these 2 values will be inversely porportional: $K_a * K_b = 10^{-14}$ $K_a = \frac{10^{-14}}{K_b}$ or $K_b = \frac{10^{-14}}{K_a}$ - When Ka increases, Kb decreases, and vice versa. Since the $K_a$ and the $K_b$ are directly related to their acids/bases strengths, the weaker the base, the stronger the conjugate acid will be, and vice versa.
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