## Chemistry 12th Edition

(a) $CH_3COO^-$: base $CH_3COOH$: conjugate acid $HCN$: acid $CN^-$: conjugate base (b) $HCO_3^-$ : base $H_2CO_3$: conjugate acid $HCO_3^-$ : acid $CO_3^{2-}$ : conjugate base (c) $H_2PO_4^-$: acid $HPO_4^{2-}$: conjugate base $NH_3$: base $NH_4^+$: conjugate acid (d) $HClO$: acid $ClO^-$: conjugate base $CH_3NH_2$: base $CH_3NH_3^+$: conjugate acid (e) $CO_3^{2-}$: base $HCO_3^-$: conjugate acid $H_2O$: acid $OH^-$: conjugate acid
Analyzing the direct reaction (left to right), the acid is the compound that loses one $(H^+)$, and the base is the one that receives this $(H^+)$. They are on the right side. The conjugate base will be the compound in the right side, that is the acid that lost its ($H^+$). The conjugate acid will be the compound in the right side, that is the base that received the ($H^+$).