Answer
(a)
$CH_3COO^-$: base
$CH_3COOH$: conjugate acid
$HCN$: acid
$CN^-$: conjugate base
(b)
$HCO_3^-$ : base
$H_2CO_3$: conjugate acid
$HCO_3^-$ : acid
$CO_3^{2-}$ : conjugate base
(c)
$H_2PO_4^-$: acid
$HPO_4^{2-}$: conjugate base
$NH_3$: base
$NH_4^+$: conjugate acid
(d)
$HClO$: acid
$ClO^-$: conjugate base
$CH_3NH_2$: base
$CH_3NH_3^+$: conjugate acid
(e)
$CO_3^{2-}$: base
$HCO_3^-$: conjugate acid
$H_2O$: acid
$OH^-$: conjugate acid
Work Step by Step
Analyzing the direct reaction (left to right), the acid is the compound that loses one $(H^+)$, and the base is the one that receives this $(H^+)$. They are on the right side.
The conjugate base will be the compound in the right side, that is the acid that lost its ($H^+$).
The conjugate acid will be the compound in the right side, that is the base that received the ($H^+$).
