Answer
a) $K_{P} = P_{CO_{2}} P_{H_{2}O}$
b) $K_{P} = P_{SO_{2}}^{2} P_{O_{2}}$
Work Step by Step
$K_{P}$ is the equilibrium constant in terms of partial pressures.
a) In this reaction, $ CO_{2}$ and ${H_{2}O}$ are in the gaseous state so we need to consider only the pressures of these gases.
Hence $K_{P} = P_{CO_{2}} P_{H_{2}O}$
b) In this reaction, $ SO_{2}$ and $O_{2}$ are in the gaseous state so we need to consider only the pressures of these gases.
Hence $K_{P} = P_{SO_{2}}^{2} P_{O_{2}}$
