Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 13 - Chemical Kinetics - Questions & Problems: 13.13

Answer

Please see the work below.

Work Step by Step

We know that $rate=K[NH_4^+][NO_2^-]$ We plug in the known values to obtain: $rate=3.0\times 10^-4(0.26M)(0.080M)$ $rate=6.2\times 10^{-6}\frac{M}{s}$
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