Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 32: 1.57


$8084.4 g$

Work Step by Step

radius: 10.0 cm density of gold: 19.3 g/cm3 Volume of sphere: $\frac{4πr^3}{3}$ =$\frac{4000π}{3}$ Mass= Density x Volume = $\frac{(19.3)(4000π)}{3}$ $\approx8084.365095 g$ $=8084.4 g$ (1 s.f.)
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