Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 19 - Acids, Bases, and Salts - 19 Assessment - Page 687: 112

Answer

.05M

Work Step by Step

.424 g Na2SO4 x 1 mole/106.0g x 1 mole H2SO4/1 mole Na2SO4 = .0004 moles H2SO4 Use the gram value and stoichiometry to convert to moles of sulfuric acid. .0004 / .0800 L = .05M Use the molarity formula (M = moles solute/L solution) to find the molarity of the sulfuric acid.
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