Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 19 - Acids, Bases, and Salts - 19 Assessment: 109

Answer

pH = 10.7

Work Step by Step

CN- + H20 -- NaOH + HCN Kb = [NaOH][HCN] / [NaCN] 0.000021 = [x][x] / 0.01M x = 0.00046 pOH = -log(OH) pOH = -log(0.00046) pOH = 3.3 pH + 3.3 = 14
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