Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 4 - The Structure of Atoms - Exercises - Electromagnetic Radiation - Page 167: 57

Answer

$3.022\times10^{-19}J/photon$

Work Step by Step

The energy per photon is given by: E = hν = $\frac{hc}{λ}$ We know: h = $6.626\times10^{-34}Js$ c = $2.997925\times10^{8}ms^{-1}$ λ = 6573 Å = $6573\times10^{-10}m$ Thus: E = $\frac{6.626\times10^{-34}Js\times2.997925\times10^{8}ms^{-1}}{6573\times10^{-10}m} = 3.022\times10^{-19}J$
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