Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - The Mole Concept - Page 75: 44

Answer

1.60×$10^{-16}$g

Work Step by Step

Recall: Number of moles= Number of molecules÷ Avogadro number. Then, number of moles= $\frac{6.00×10^{6}}{6.022×10^{23}}$= $9.96×10^{-18}$mol. Mass in grams = Number of moles×Molar mass = $9.96×10^{-18}mol×16.04g/mol$= $1.60×10^{-16}g$
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