# Chapter 2 - Chemical Formulas and Composition Stoichiometrhy - Exercises - The Mole Concept - Page 75: 36

0.734 mol

#### Work Step by Step

Mass, m= 12.50 g Molar mass, M= 3$\times$1.008g + 1$\times$14.007=17.031 Using relation n=$\frac{m}{M}$ , We get , n=0.734 mol

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