Answer
5.20 atm
Work Step by Step
Given, n= 2.54 mol
T= (273+45) K = 318 K
V= 12.75 L
Using Ideal gas equation,
P = $\frac{nRT}{V}$ = $\frac{2.54mol(0.0821\frac{L.atm}{mol.K})318K}{12.75L}$ = 5.20 atm
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