Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - The Ideal Gas Equation - Page 442: 50

0.88 g

Work Step by Step

V = 5.0 L P = 1.1 atm T = (25+273) K = 298 K Use ideal gas law to obtain, n= $\frac{PV}{RT}$ =$\frac{1.1atm\times5.0L}{(0.0821\frac{L.atm}{mol.K})298K}$ =0.22 mol. We know, Mass in grams=number of moles$\times$molar mass= 0.22mol$\times$$4.003 gmol^{-1}$=0.88g

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