Answer
0.88 g
Work Step by Step
V = 5.0 L
P = 1.1 atm
T = (25+273) K = 298 K
Use ideal gas law to obtain, n= $\frac{PV}{RT}$ =$\frac{1.1atm\times5.0L}{(0.0821\frac{L.atm}{mol.K})298K}$ =0.22 mol.
We know,
Mass in grams=number of moles$\times$molar mass=
0.22mol$\times$$4.003 gmol^{-1}$=0.88g