Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - The Combined Gas Law: 33

Answer

4.68$\times10^{3}$ torr

Work Step by Step

Using combined gas law, $P_{2}$ = $\frac{P_{1}\times V_{1}\times T_{2}}{T_{1}\times V_{2}}$ =$\frac{760torr\times363 mL\times1092 K}{273K\times236mL}$$\approx 4.68\times10^{3}$ torr. 4675 torr when rounded to 3 significant figures became 4.68$\times10^{3}$ torr. The rule is to increase the value by 1 if the digit before 5 is odd.
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