## Chemistry 10th Edition

4.68$\times10^{3}$ torr
Using combined gas law, $P_{2}$ = $\frac{P_{1}\times V_{1}\times T_{2}}{T_{1}\times V_{2}}$ =$\frac{760torr\times363 mL\times1092 K}{273K\times236mL}$$\approx 4.68\times10^{3}$ torr. 4675 torr when rounded to 3 significant figures became 4.68$\times10^{3}$ torr. The rule is to increase the value by 1 if the digit before 5 is odd.