Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - The Combined Gas Law - Page 441: 33


4.68$\times10^{3}$ torr

Work Step by Step

Using combined gas law, $P_{2}$ = $\frac{P_{1}\times V_{1}\times T_{2}}{T_{1}\times V_{2}}$ =$\frac{760torr\times363 mL\times1092 K}{273K\times236mL}$$\approx 4.68\times10^{3}$ torr. 4675 torr when rounded to 3 significant figures became 4.68$\times10^{3}$ torr. The rule is to increase the value by 1 if the digit before 5 is odd.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.