Answer
337$^{\circ}$C
Work Step by Step
$V_{1}$ = 385 mL
$T_{1}$ = (26+273) K = 299 K
$P_{1}$ = 670. torr
$P_{2}$ = 940. torr
$V_{2}$ = 560. mL
Using combined gas law,
$T_{2}$ =$\frac{P_{2}\times V_{2}\times T_{1}}{P_{1}\times V_{1}}$= $\frac{940. torr\times560. mL\times299K}{670.torr\times385 mL}$= 610. K or (610.-273)$^{\circ}$C
