## Chemistry 10th Edition

$V_{1}$ = 1.50 L $P_{1}$ =1.00 atm $P_{2}$ =2.50 atm $V_{2}$ =$\frac{P_{1}\times V_{1}}{P_{2}}$ = $\frac{1.00 atm\times 1.50 L}{2.50 atm}$ = 0.60 L