# Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - Boyle's Law: The Pressure-Volume Relationship - Page 439: 15

0.60 L

#### Work Step by Step

$V_{1}$ = 1.50 L $P_{1}$ =1.00 atm $P_{2}$ =2.50 atm $V_{2}$ =$\frac{P_{1}\times V_{1}}{P_{2}}$ = $\frac{1.00 atm\times 1.50 L}{2.50 atm}$ = 0.60 L

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