Answer
0.60 L
Work Step by Step
$V_{1}$ = 1.50 L
$P_{1}$ =1.00 atm
$P_{2}$ =2.50 atm
$V_{2}$ =$\frac{P_{1}\times V_{1}}{P_{2}}$ = $\frac{1.00 atm\times 1.50 L}{2.50 atm}$ = 0.60 L
Chemistry 10th Edition
by Whitten, Kenneth W.; Davis, Raymond E.; Peck, Larry; Stanley, George G.
Published by
Brooks/Cole Publishing Co.
ISBN 10:
1133610668
ISBN 13:
978-1-13361-066-3
Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - Boyle's Law: The Pressure-Volume Relationship - Page 439: 15
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