Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - Boyle's Law: The Pressure-Volume Relationship - Page 439: 14


1.06 atm

Work Step by Step

$V_{1}$ =300. mL $P_{1}$ =2.00 atm $V_{2}$ =567 mL $P_{1}\times$$V_{1}$= $P_{2}\times$$V_{2}$ Or $P_{2}$ = $\frac{P_{1}\times V_{1}}{V_{2}}$ = $\frac{2.00 atm \times 300.mL}{567 mL}$= 1.06 atm
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