## Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.

# Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - Boyle's Law: The Pressure-Volume Relationship: 14

1.06 atm

#### Work Step by Step

$V_{1}$ =300. mL $P_{1}$ =2.00 atm $V_{2}$ =567 mL $P_{1}\times$$V_{1}= P_{2}\times$$V_{2}$ Or $P_{2}$ = $\frac{P_{1}\times V_{1}}{V_{2}}$ = $\frac{2.00 atm \times 300.mL}{567 mL}$= 1.06 atm

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