Answer
1.06 atm
Work Step by Step
$V_{1}$ =300. mL
$P_{1}$ =2.00 atm
$V_{2}$ =567 mL
$P_{1}\times$$V_{1}$= $P_{2}\times$$V_{2}$
Or $P_{2}$ = $\frac{P_{1}\times V_{1}}{V_{2}}$ = $\frac{2.00 atm \times 300.mL}{567 mL}$= 1.06 atm
Chemistry 10th Edition
by Whitten, Kenneth W.; Davis, Raymond E.; Peck, Larry; Stanley, George G.
Published by
Brooks/Cole Publishing Co.
ISBN 10:
1133610668
ISBN 13:
978-1-13361-066-3
Chapter 12 - Gases and the Kinetic-Molecular Theory - Exercises - Boyle's Law: The Pressure-Volume Relationship - Page 439: 14
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