Answer
.11465 mol/L
Work Step by Step
41.4 g $\div$ 120.366 g/mol = .34395 mol
.34395 mol $\div$ 3 L = .11465 mol/L
Chemistry 10th Edition
by Whitten, Kenneth W.; Davis, Raymond E.; Peck, Larry; Stanley, George G.
Published by
Brooks/Cole Publishing Co.
ISBN 10:
1133610668
ISBN 13:
978-1-13361-066-3
Chapter 11 - Reactions in Aqueous Solutions II: Calculations - Exercises - Molarity - Page 394: 4
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