Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 11 - Reactions in Aqueous Solutions II: Calculations - Exercises - Molarity - Page 394: 17

Answer

2.89 M

Work Step by Step

Let the volume of the solution be 1 L. $\text{Mass of the solution}=\text{Density}\times\text{Volume}$ $=0.979\, g/mL\times1000\, mL=979\,g$ $\text{Mass of ammonia}=979\,g\times\frac{5.03}{100}$ $=49.2437\, g$ $\text{Moles of ammonia}=\frac{49.2437\,g}{17.031\,g/mol}$ $=2.89\, mol$ $\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}$ $=\frac{2.89\,mol}{1\,L}=2.89\,M$
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