Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.5 - Vectors: An Algebraic Approach - 7.5 Problem Set - Page 404: 35

Answer

$\frac{1}{2}V=(-1.5,3.5)$ $-V=(3,-7)$ $4V=(-12,28)$

Work Step by Step

$V=(-3,7)$ $\frac{1}{2}V=(\frac{1}{2}(a),\frac{1}{2}(b))$ $\frac{1}{2}V=(-1.5,3.5)$ $-V=(-a,-b)$ $-V=(--3,-7)$ $-V=(3,-7)$ $4V=(4(a),4(b))$ $4V=(4(-3),4(7))$ $4V=(-12,28)$
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