Chapter 7 - Section 7.5 - Vectors: An Algebraic Approach - 7.5 Problem Set - Page 404: 30

$|V|=2.$

The magnitude of a vector is given by the possible square root of the sum of the squares of its horizontal and vertical components. Let $V=\langle 2,0\rangle.$ Then \begin{align*} |V|&=\sqrt{(2)^{2}+(0)^{2}}\\ &=\sqrt{4+0}\\ &=\sqrt{4}\\ &=2. \end{align*} Hence, $|V|=2.$