## Trigonometry 7th Edition

$\theta=47.6^{\circ}\,or\,132.4^{\circ}$
$\sin\theta=0.7380$ We know that, $0\leq\,\theta\lt360^{\circ}$ sin function is positive in Quadrants 1 and 2. So, $\theta=\sin^{-1}(0.7380)=47.6^{\circ}\,or\,180^{\circ}-47.6^{\circ}=132.4^{\circ}$ So, $\theta=47.6^{\circ}\,or\,132.4^{\circ}$