Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.1 - The Law of Sines - 7.1 Problem Set - Page 371: 45


$\theta=90^{\circ}or \,270^{\circ}$

Work Step by Step

$\sin\theta\cos\theta-2\cos\theta=0$ $\cos \theta(\sin\theta-2)=0$ So, either $\cos\theta=0\,or\,\sin\theta=2$ When, $\cos\theta=0,$ $\theta=90^{\circ},270^{\circ}$ Now, $\sin\theta=2$ is not possible, since $|\sin\theta|\leq1$ For, $0^{\circ}\leq\,x\lt360^{\circ}$ So, $\theta=90^{\circ}or \,270^{\circ}$
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