Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 6 - Section 6.3 - Trigonometric Equations Involving Multiple Angles - 6.3 Problem Set - Page 339: 10

Answer

$\theta=\{90^o,210^o,330^o\}$

Work Step by Step

$sin(3\theta)=-1$ $3\theta=sin^{-1}(-1)$ The period of the sine function is $360^o$ $3\theta=270^o\;\;\;\;or\;\;\;\;\;\;3\theta=360^o+270^o\;\;\;\;or\;\;\;\;\;\;3\theta=720^o+270^o\;\;\;\;\;\;\;\;\;\;$ $\theta=90^o\;\;\;\;or\;\;\;\;\;\;\theta=210\;\;\;\;or\;\;\;\;\;\;\theta=330^o\;\;\;\;\;\;\;\;\;\;\;\;\;$ $\theta=\{90^o,210^o,330^o\}$
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