Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 6 - Section 6.1 - Solving Trigonometric Equations - 6.1 Problem Set - Page 327: 78

Answer

$$\cos 2A =2\cos^2A-1$$

Work Step by Step

We find: \begin{align*} \cos 2A&=\cos^2A-\sin^2A,\ \ \ \ \ \ \ \ \ \text{Use }\cos^2x+\sin^2x=1 \\ &=\cos^2A-(1-\cos^2A)\\ &=2\cos^2A-1 \end{align*}
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