Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 6 - Section 6.1 - Solving Trigonometric Equations - 6.1 Problem Set - Page 327: 76

Answer

$$ \theta=\sin^{-1}\left(\frac{894}{4500}\right)\approx 11.46^{\circ}$$

Work Step by Step

Since $$ h=-16t^2+vt \sin\theta $$ at $ v=1500, \ \ h= 750,\ \ t=3$, then \begin{aligned} h&=-16t^2+vt \sin\theta \\ 750&=-16(9)+4500 \sin\theta \\ 894&= 3000 \sin\theta\\ \sin\theta &=\frac{894}{4500} \end{aligned} hence $ \theta=\sin^{-1}\left(\frac{894}{4500}\right)\approx 11.46^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.