## Trigonometry 7th Edition

$(a)$ $\theta=30^{o}+360^{o}k$ or $\theta=330^{o}+360^{o}k$ $(b)$ $30^{o}$ and $330^{o}.$
The first task is to isolate the trigonometric function on one side: Add $\sqrt{3}$ to both sides... $2\cos\theta=\sqrt{3}\qquad$ ... divide with 2 $\displaystyle \cos\theta=\frac{\sqrt{3}}{2}$ Now, we find a reference angle. From the table of characteristic angles, we know that $\displaystyle \cos 30^{o}=\frac{\sqrt{3}}{2}.$ Next, we know that cosine is positive in quadrant IV as well, so another angle that satisfies the equation is $360^{o}-30^{o}=330^{o}$ Finally, to each individual solution, add multiples of $360^{o}$ to cover all solutions: $(a)$ $\theta=30^{o}+360^{o}k$ or $\theta=330^{o}+360^{o}k$ $(b)$ The solutions within the interval $0^{o}\leq\theta \lt 360^{o}:$ $30^{o}$ and $330^{o}.$