Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.4 - Arc Length and Area of a Sector - 3.4 Problem Set - Page 155: 42

Answer

$\frac{16}{5\pi}=\approx1.02$ km

Work Step by Step

We know that the length of the arc $s$ cut off by $\theta$ can be calculated as $s=r\theta$. Therefore, we also know that $r=\frac{s}{\theta}$. We are given that $\theta=225^{\circ}$ and $s=4$ km. We can convert $\theta$ to radians by multiplying $\theta$ by $\frac{\pi}{180}$. $\theta=225^{\circ}=225(\frac{\pi}{180})=\frac{225\pi}{180}=\frac{5\pi}{4}$ Therefore, $r=\frac{4}{\frac{5\pi}{4}}=4\times\frac{4}{5\pi}=\frac{4\times4}{5\pi}=\frac{16}{5\pi}=\approx1.02$ km.
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