Answer
$\sin{180^o} = 0
\\\cos{180^o} = -1
\\\tan{180^o} = 0
\\\cot{180^o} \text{ is undefined}
\\\csc{180^o} \text{ is undefined}
\\\sec{180^o} = -1$
Work Step by Step
RECALL:
If $P(x, y)$ is on a unit circle, then
$\begin{array}{cc}
&\cos{\theta} = x &\sec{\theta} = \frac{1}{x}, x\ne 0
\\&\sin{\theta} = y &\csc{\theta} = \frac{1}{y}, y\ne 0
\\&\tan{\theta} = \frac{y}{x}, x\ne 0 &\cot{\theta} = \frac{x}{y}, y \ne 0
\end{array}$
Refer to the unit circle on page 137 of this textbook.
Thus, using the ratios in the recall part above, and with $P(-1, 0)$, gives:
$\sin{180^o} = 0
\\\cos{180^o} = -1
\\\tan{180^o} = \dfrac{0}{-1} =0
\\\cot{180^o}=\dfrac{-1}{0} \text{( undefined)}
\\\csc{180^o}=\dfrac{1}{0} \text{( undefined)}
\\\sec{180^o} = \frac{1}{-1}=-1$