Answer
$-\sqrt3$
Work Step by Step
RECALL:
In a unit circle
$\cos {t}=x
\\\sin{t}=y
\\\tan{t} = \dfrac{y}{x}, x\ne0
\\\cot{t} = \dfrac{x}{y}, y \ne 0
\\\sec{t} = \dfrac{1}{x}, x\ne0
\\\csc{t} = \dfrac{1}{y}, y \ne0$
Using the definition above and the unit circle in Figure 5 on page 137 of this book, then:
Point on the unit circle: $\left(\dfrac{1}{2}, -\dfrac{\sqrt3}{2}\right)$
Thus,
$\tan{300^o} = \dfrac{y}{x} = \dfrac{-\frac{\sqrt3}{2}}{\frac{1}{2}}=\dfrac{-\sqrt3}{2} \cdot \dfrac{2}{1}=-\sqrt3$