## Trigonometry 7th Edition

$240^{\circ}$
Given- $\tan\theta$ = $\sqrt 3$ , $\theta$ belongs to Q III We will find reference angle of $\theta$ first using value $\sqrt 3$ and reference angle theorem- $\tan\theta$ = $\sqrt 3$ = $\tan 60^{\circ}$ (As $\tan 60^{\circ}$ = $\sqrt 3$) Therefore by reference angle theorem, $60^{\circ}$ is the reference angle for desired angle $\theta$ The desired angle $\theta$ is in Q III, Also $0^{\circ}\leq \theta\lt 360^{\circ}$ Therefore- $\theta$ = $180^{\circ} + 60^{\circ}$ = $240^{\circ}$