Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.1 - Reference Angle - 3.1 Problem Set - Page 122: 26

Answer

2

Work Step by Step

To find exact value of $\csc (-330)^{\circ}$, let's find its reference angle first. As $ (-330)^{\circ}$ terminates in quadrant I, The reference angle = $ 360^{\circ} - 330^{\circ} $ = $30^{\circ}$ As $ (-330)^{\circ}$ terminates in quadrant I, its $\csc$ will be positive. Therefore by reference angle theorem- $\csc (-330)^{\circ}$ = $\csc 30^{\circ}$ = 2
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.