Answer
Chapter 2 - Section 2.3 Problem Set: 51 (Answer)
Refer to Figure 1
$h = 18$ (To 2 significant digits)
$x = 11$ (To 2 significant digits)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 51 (Solution)
Refer to Figure 1
In $\triangle$BAC,
$\sin A$ = $\frac{h}{AB}$
$\sin 41^{\circ}$ = $\frac{h}{28}$
$h = 28 \cdot \sin 41^{\circ}$
$h = 18$ (To 2 significant digits)
In $\triangle$BDC,
$\tan\angle BDC$ = $\frac{h}{x}$
$\tan 58^{\circ}$ = $\frac{18}{x}$
$x = \frac{18}{\tan 58^{\circ}}$
$x = 11$ (To 2 significant digits)
