Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.3 - Solving Right Triangles - 2.3 Problem Set - Page 81: 47

Answer

Chapter 2 - Section 2.3 Problem Set: 47 (Answer) Refer to Figure I $\angle ABD$ = $42^{\circ}$ (To the nearest digit)

Work Step by Step

Chapter 2 - Section 2.3 Problem Set: 47 (Solution) Refer to Figure I In $\triangle$ABC, $\sin 41^{\circ} = \frac{x}{32}$ $x = 32 \cdot \sin 41^{\circ}$ $x = 21$ (To the nearest digit) In $\triangle$DAB, $\tan(\angle ABD)$ = $\frac{h}{x}$ $\tan(\angle ABD)$ = $\frac{19}{21}$ $\angle ABD$ = $\tan^{-1}(\frac{19}{21})$ $\angle ABD$ = $42^{\circ}$ (To the nearest digit)
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