Answer
Chapter 2 - Section 2.3 Problem Set: 49 (Answer)
Refer to Figure 1
$x = 7.4$ (To 2 significant digits)
$y = 6.2$ (To 2 significant digits)
Work Step by Step
Chapter 2 - Section 2.3 Problem Set: 49 (Solution)
Refer to Figure 1
In $\triangle$BDC,
$\cos\angle BDC$ = $\frac{x}{DB}$
$\cos 58^{\circ}$ = $\frac{x}{14}$
$x = 14 \cdot \cos 58^{\circ}$
$x = 7.4$ (To 2 significant digits)
In $\triangle$BAC,
$\cos A$ = $\frac{AC}{AB}$
$\cos 41^{\circ}$ = $\frac{(7.4+y)}{18}$
$7.4 + y = 18 \cdot \cos 41^{\circ}$
$y = 6.2$ (To 2 significant digits)
