Answer
A. symmetry with respect to the origin
Work Step by Step
Whenever $(r, \theta)$ is on the graph, so is $(-r, \theta)$.
$(-r, \theta) = (r, 180^{\circ}+\theta)$
Therefore, whenever $(r, \theta)$ is on the graph, so is $(r, 180^{\circ}+\theta)$.
Then the graph will have symmetry with respect to the origin.