Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Review Exercises - Page 405: 61

Answer

$ r=\tan\theta\sec\theta$ or $r=\frac{\tan\theta}{\cos\theta}$

Work Step by Step

$y=x^{2}$ Convert it into polar co-ordinates. $r sin\theta=r^{2}\cos^{2}\theta$ This implies, $ \sin\theta=r\cos^{2}\theta$ $ r=\frac{\sin\theta}{\cos^{2}\theta}$ Hence, $ r=\frac{\sin\theta}{cos\theta}\times\frac{1}{\cos\theta}=\tan\theta\sec\theta$ or $r=\frac{\tan\theta}{\cos\theta}$
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