Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 7 - Test - Page 347: 14

Answer

The height of the balloon is 2.7 miles above the ground.

Work Step by Step

We can find the angle $C$: $A+B+C = 180^{\circ}$ $C = 180^{\circ}-A-B$ $C = 180^{\circ}-24^{\circ}50'-47^{\circ}20'$ $C = 107^{\circ}50'$ We can use the law of sines to find the length of side $BC$: $\frac{BC}{sin~A} = \frac{AB}{sin~C}$ $BC = \frac{AB~sin~A}{sin~C}$ $BC = \frac{(8.4~mi)~sin~24^{\circ}50'}{sin~107^{\circ}50'}$ $BC = 3.7~mi$ We can find the height $h$ of the balloon: $\frac{h}{BC} = sin~47^{\circ}20'$ $h = (BC)~sin~47^{\circ}20'$ $h = (3.7~mi)~sin~47^{\circ}20'$ $h = 2.7~mi$ The height of the balloon is 2.7 miles above the ground.
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