Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 7 - Test - Page 347: 1

Answer

$C \approx 137.5^{\circ}$

Work Step by Step

1. Find $\angle B$ $\frac{\sin (B)}{b} = \frac{\sin (A)}{a}$ $\frac{\sin(B)}{4.82} = \frac{\sin (25.2)}{6.92}$ $\sin(B) = \frac{4.82\sin(25.2)}{6.92}$ $\sin B = 0.29656...$ $B = \sin^{-1} (0.29656...)$ $B = 17.2516...^{\circ}$ 2. Find $\angle C$ $\angle C = 180 - (\angle A + \angle B)$ $= 180 - [25.2 + (17.2516...)]$ $= 180 - (42.4516...)$ $= 137.54836...^{\circ}$ $\approx 137.5^{\circ}$
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