## Trigonometry (10th Edition)

We can use the law of cosines to find the length $AB$: $AB^2 = AC^2+BC^2-2(AC)(BC)~cos~C$ $AB = \sqrt{AC^2+BC^2-2(AC)(BC)~cos~C}$ $AB = \sqrt{(350~m)^2+(286~m)^2-(2)(350~m)(286~m)~cos~46.3^{\circ}}$ $AB = \sqrt{65981.34~m^2}$ $AB = 257~m$ AB has a length of 257 m