Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 5 - Trigonometric Identities - Section 5.3 Sum and Difference Identities for Cosine - 5.3 Exercises - Page 212: 5

Answer

5 is matched with E.

Work Step by Step

According to the given identity, we have that $$\cos(x-\frac{\pi}{2})=\sin x$$ which is a little unlike the fifth expression. So we need do some transformations: $$\cos(\frac{\pi}{2}-x)$$ $$=\cos[-(x-\frac{\pi}{2})]$$ Yet we already know that $\cos(-X)=\cos X$. Therefore, $$=\cos(x-\frac{\pi}{2})$$ $$=\sin x$$ Now we match with the expressions in II. We find that the fifth expression in I matches the expression E in II. Therefore, we would match 5 with E to have an identity.
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