Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 4 - Review Exercises - Page 184: 48

Answer

$\color{blue}{y=2 \cdot \csc{x} - 1}$.

Work Step by Step

The graph looks like that of the basic cosecant function $y=\csc{x}$. The period of the given function is $2\pi$, the same as that of the basic cosecant function. This means that the tentative equation of the function whose graph is given is $y=a\cdot csc{x}+c$ The vertices of the two U-shaped curves of the basic cosecant function $y=\csc{x}$, where $a=1$, are $(\frac{\pi}{2}, 1)$ and $(\frac{3\pi}{2}, -1)$. These vertices are equidistant from the line $y=0$. The distance between these two vertices is 2 units. In the given graph, the distance between the two vertices is: $=1-(-3) \\=1+3 \\=4$ This means that $a= \frac{4}{2}=2$. ($a$ is positive since the graph does not involve a reflection about the x-axis of the basic cosecant function.) Notice that in the given graph, the vertices are equidistant from the line $y=-1$. This means that the function involves a $1$-unit shift downwards of the parent function. Therefore, the equation of the function whose graph is given must be $\color{blue}{y=2 \cdot \csc{x} - 1}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.